Question
limit n tends to ∞
then
(x^n)/(n!) equals
Joshi sir comment
let y = lim n->∞ (xn/n!)
or y = x lim n->∞ (1/n) lim n->∞ xn-1/(n-1)!
or y = 0
limit n tends to ∞
then
(x^n)/(n!) equals
let y = lim n->∞ (xn/n!)
or y = x lim n->∞ (1/n) lim n->∞ xn-1/(n-1)!
or y = 0