Question
6.3g of hydrated oxalic acid is treated with M/20 Mg(OH)2. The volume of Mg(OH)2 used for complete neutralisation is
Joshi sir comment
gm eq of oxalic acid = 6.3/63 = 0.1
gm eq of Mg(OH)2 = (1/20)*2*V
now compare the two
6.3g of hydrated oxalic acid is treated with M/20 Mg(OH)2. The volume of Mg(OH)2 used for complete neutralisation is
gm eq of oxalic acid = 6.3/63 = 0.1
gm eq of Mg(OH)2 = (1/20)*2*V
now compare the two