Question

The dissociation constant of a weak acid  HA and weak base BOH are 2 x 10-5 and 5 x 10-6 respectively. The equilibrium constant for the neutralization reaction of the two is (ignore hydrolysis of resuting salt)

Joshi sir comment

HA + BOH ------------------>  B+ + A- + H2O

K = [B+][A-][H2O]/[HA][BOH]

  = [B+][OH-]/[BOH] *  [H+][A-]/[HA] *  [H2O]/[H+][OH-] = Kb *  Ka  /  Kw

now solve 

Read 1 Solution.

HA + BOH ------------------>  B+ + A- + H2O

K = [B+][A-][H2O]/[HA][BOH]

  = [B+][OH-]/[BOH] *  [H+][A-]/[HA] *  [H2O]/[H+][OH-] = Kb *  Ka  /  Kw

now solve 

10 year ago is this solution helpfull: 20 100

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