Question
The change in standard gibbs free energy of given cell at NTP
Zn I Zn(2+) II OH- I Ag2O I Ag Eo =1.104V
Joshi sir comment
Zn -----> Zn++ + 2e-
Ag2O + H2O + 2e- ------> 2Ag + 2OH-
so Gibbs free energy change = nFE = 2*96500*1.104
The change in standard gibbs free energy of given cell at NTP
Zn I Zn(2+) II OH- I Ag2O I Ag Eo =1.104V
Zn -----> Zn++ + 2e-
Ag2O + H2O + 2e- ------> 2Ag + 2OH-
so Gibbs free energy change = nFE = 2*96500*1.104