Question

A disc of mass 3kg rolls down an inclined plane of height 5 m. The translational kinetic energy of the disc on reaching the bottom of the inclined plane is

Joshi sir comment

mgh = 1/2 mv2 + 1/2 Iω2

I for the disc about centre = 1/2 MR

and for pure rolling v = Rω

calculate v then 1/2 mv2

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