Question
A capacitor of capacity 0.1 μF connected in series to a resistor of 10 MΩ is charged to a certain potential and then made to discharge through resistor. The time in which the potential will take to fall to half its original value is (Give, log102 = 0.3010)
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ARCHITA GUPTA 7 year ago
is this solution helpfull: 2 0
V0/2=Voe-t/RC
1/2=e-t/RC
loge2=t/RC
t=RCloge2
t=10 χ 106 χ 0.1 χ 10-6 loge2
t=0.693s
ARCHITA GUPTA 7 year ago
is this solution helpfull: 3 0