Question
A weightless rod of length l carries two equal masses m one fixed at the end and other in the middle of the rod. The rod can revolve in a vertical plane about A. Then horizontal velocity which must be imparted to end C of rod to deflect it to horizontal position...
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since torque=f*l;
snce to prevent rotatin torque=0;
so let torque=t
so t= -f+ ml/2 ml
but t=0(equlibrium condition)
s f=3ml/2
SHOUNAK BOSE 9 year ago
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