Question
If A+B+C=180, then secA(cosBcosC-sinBsinC) is equal toRead 1 Solution.
=-1/cos(B+C)[cosBcosC-sinBsinC]
=-[cos(B+C)]/cos(B+C)
=-1
C NARENDRA CHARY 8 year ago
is this solution helpfull: 0 2
=-1/cos(B+C)[cosBcosC-sinBsinC]
=-[cos(B+C)]/cos(B+C)
=-1