Question

A hydrogen like system has ionisation enthalpy 11808KJ/mol. find the no of protons in the nucleus of the system?

 

Joshi sir comment

A hydrogen like system has ionisation enthalpy 11808KJ/mol

on converting it into eV we get [11808*1000]/[6.023*1023*1.6*10-19]  = 122.53 eV

now formula for this energy is [-Z2/n2]13.6 eV

for n = 1, Z will be 3

 

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