Question
A bus starts moving with an acceleration of 2m/s2. A cyclist 96m behind the bus starts simultaneously towards the bus at 20 m/s . After what time cyclist will be able to overtake the bus?
Joshi sir comment
let after time t
then distance covered by cyclist in this time = 20t
and by bus = 2t2 / 2 = t2
so according to the given condition
20t = 96+t2
so t = 8,12
after 8 sec cyclist overtakes bus and after 12 sec bus overtakes cyclist