Question
a body thrown vertically up with initial velocity 52 m/s from the ground passes twice a point at h height above at an interval of 10s. The height h is...........
(g=10m/s2)
Joshi sir comment
from that point to topmost point, time taken = 10/2 = 5 sec
so velocity at that point = 50 m/s
now use
522 = 502- 2gh
solve