Question
When a particle is thrown vertically upwards, its velocity at one third of its maximum height is 10√2 m/s. The maximum height attained by it is......
Joshi sir comment
remaining height = 2h/3
so 02 = (10√2)2 - 2g(2h/3)
solve
Read 1 Solution.
We know that
at maximun height, velocity is zero
Therefore, u2 - 2gh = 0
u2= 2gh ........ (1)
Given that u= 10 root 2 m/s
h=h/3
substitute in (1)
(10 root 2 )2 = 2g(h/3)
100 (2) = 2g(h/3)
200 = 2(10)(h/3) since g = 10m/s^2
600 = 20h
h = 30 m
THEREFORE THE MAXIMUM HEIGHT IS 30m
DEVIKA 6 year ago
is this solution helpfull: 9 108