Question
A resistor of 10kΩ having tolerance 10 % is connected in series with another resistor of 20 kΩ having tolerance 20 %. The tolerance of the combination will be approximately.
Joshi sir comment
resultant = (10±1)+(20±4) = 30±5
so tolerance = 5*100/30 = 50/3 = 16.67 %