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Question

The distance between two parallel lines is 1.A point 'A' is chosen to lie between the lines at a distance 'd' from the first line. Triangle ABC is an eqilateral triangle with 'B" on one line and 'C' on the other line.Then AB is equal to(in terms of d).

Joshi sir comment

In triangle BCX

BC = seca

so AB = seca

now in triangle ABY

cos(60+a) = d/seca

so 1/2 cosa - √3/2 sina = d cosa

or tana = (1-2d)/√3

now calculate seca

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