Question
Integral enthalpy of soln of KCl , when 1 mole of it is dissolved in 20 mole water is +15.90kJ . When 1 mole of it is dissolved in 200mole water dH =15.58kJ. Calculate enthalpy of hydratn or dilutn ??
ans is 2.68kJ
Joshi sir comment
Integral enthalpy
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Read 2 Solution.
The qn has a small error which made it damn confusing . dH in second case is 18.58 kJ n now dH hyd = 18.58-15.90 = 2.68 kJ (Note : in qns relating to dilution subtract dH finite from dH infinite dilution)
RAHUL JOHN JOSEPH 11 year ago
is this solution helpfull: 6 1
The qn has a small error which made it damn confusing . dH in second case is 18.58 kJ n now dH hyd = 18.58-15.90 = 2.68 kJ (Note : in qns relating to dilution subtract dH finite from dH infinite dilution)
RAHUL JOHN JOSEPH 11 year ago
is this solution helpfull: 3 1