Question
the velocity v of a particle moving in the positive direction of x - axis as v = 5√x, assuming that at t=0, particle was at x=0. What is the acceleration of the particle?
Joshi sir comment
v = 5√x
differetiate this we get
dv/dt = 5*1/(2√x)*dx/dt
so a = 5*1/(2√x)*v
so a = 5*1/(2√x)*5√x
so a = 12.5