Question

Two oxides of a metal M contain respectively 22.53% and 30.38% of O2. If the formula of first oxide is MO, the formula of second oxide is

(a) M2O3         (b) MO3         (c) M2O         (d) M2O4

Joshi sir comment

                        M                          O

                     77.47                   22.53

m w               M                           16

formula for first oxide is MO

so 77.47/M = 22.53/16 

so M = 77.47*16/22.53 = 55

 

                    M                         O

               69.62                   30.38

m w         55                         16

so M:O = 69.62/55:30.38/16 = 1.27:1.90

1.9/1.27 = 1.5

so formula will be M2O3

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