Question
The ph of 0.1 M HCN is 5.2. What is the Ka?
Joshi sir comment
HCN -------------------> H+ + CN-
0.1 0 0
0.1-x x x
pH = 5.2
so -log[H+] = 5.2
solve for [H+], it will give x
then calculate Ka
The ph of 0.1 M HCN is 5.2. What is the Ka?
HCN -------------------> H+ + CN-
0.1 0 0
0.1-x x x
pH = 5.2
so -log[H+] = 5.2
solve for [H+], it will give x
then calculate Ka