Question
Calculate the percentage ionization of 0.01 M acetic acid in 0.1 M HCl. Ka of acetic acid is 1.8 x 10-5
Joshi sir comment
CH3COOH ----------------> CH3COO- + H+
0.01 0 0.1
0.01-x x 0.1+x
0.1+x =0.1 for x is negligibly small
so Ka = x*0.1/(0.01-x)
now solve