Question
A particle of mass 5 kg is moving with a uniform speed 3√2 in XOY plane along Y = X + 4. The magnitude of its angular momentum about the origin is
Solution by Joshi sir.
perpendicular distance of the line x-y+4 = 0 from origin
= (0-0+4)/√2
so angular momentum = mvr = 5*(3√2)*4/√2 = 60