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Question

A horizontal disc rotating freely about a vertical axis through its centre makes 90 revolutions per minute. A small piece of wax of mass m falls vertically on the disc and sticks to it at a distance r from the axis. If the number of revolutions per minute reduce to 60, then the moment of inertia of the disc is

Joshi sir comment

use I₁ω₁ = I₂ω₂

let moment of inertia of disc about given axis is I

then I2π90/60 = [I+mr²]2π60/60

solve it

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