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Question

A disc of mass 3kg rolls down an inclined plane of height 5 m. The translational kinetic energy of the disc on reaching the bottom of the inclined plane is

Joshi sir comment

mgh = 1/2 mv² + 1/2 Iω²

I for the disc about centre = 1/2 MR²

and for pure rolling v = Rω

calculate v then 1/2 mv²

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