Question
A taxi leaves the station X for Station Y every 10 min. Simulataneously, a taxi also leaves the station Y for station X Every 10min. The Taxis move at the same constant speed and go from X to Y or Viceversa in 2Hours. How Many taxis coming from the other side meet each taxi enroute from Y To X?
the answer depends on the condition that where taxi meets with the first taxi coming from opposite side.
If we consider that at the starting point taxi meets with the first taxi coming from other side, then after every 5 min it will meet with a taxi from opposite side. This will be due to the double relative speed of two taxi moving opposite. Total time length of the path = 2 hrs = 120 min
so no. of taxi = 120/5 + 1 = 25
if first taxi meet at the point a little ahead the starting point then no of taxi = 120/5 = 24
similarly other cases