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Question

A ball is dropped from the top of the tower of height h. It covers a distance h/2 in the last second of its motion. How long does the ball remain in air?

Joshi sir comment

let total time of flight = t

so h = gt²/2 and

h/2 = gt-(g/2)

so gt²/4 = gt-(g/2)

or t²/4 = t -(1/2)

now solve

Read 1 Solution.

h= 0+(1/2) g t^2

h/2= 0+g/2 (2t-1)

divide the above two eqn ,then u will finally get a quadratic eqn then solve it to find value of t that value of t will be the time for which the ball was in the air

SARIKA SHARMA 11 year ago is this solution helpfull: 30 30

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