Question
How to inegrate ( In t) dt /(t-1)
Joshi sir comment
let lnt = x so dt/t = dx so dt = tdx = exdx
now ∫(ln t)dt/(t-1) = ∫xexdx/(ex-1) = ∫x(ex-1+1)dx/(ex-1)
now solve
How to inegrate ( In t) dt /(t-1)
let lnt = x so dt/t = dx so dt = tdx = exdx
now ∫(ln t)dt/(t-1) = ∫xexdx/(ex-1) = ∫x(ex-1+1)dx/(ex-1)
now solve