Question
In order to raise a mass of 100 kg, a man of mass 60 kg fastens a rope to it and passes the rope over a smooth pulley. He climbes the rope with an acceleration 5g/4 relative to the rope. The tension of the rope is:
(a) 1432 N
(b) 928 N
(c) 1218 N
(d) 642 N
Joshi sir comment
eq. for upward motion of 100 Kg is T-100g = 100a (1)
for man eq. is T-60g = 60[(5g/4)-a] from ground frame
solve?