Question
The length of wire, when M1 is hung from it, is l1 and is l2 with both M1 and M2 hanging. The natural length of wire is [ M2 is on M1 ]
Joshi sir comment
Y = M1gL/A(l1-L) = (M1+M2)gL/(l2-L)
solve for L
The length of wire, when M1 is hung from it, is l1 and is l2 with both M1 and M2 hanging. The natural length of wire is [ M2 is on M1 ]
Y = M1gL/A(l1-L) = (M1+M2)gL/(l2-L)
solve for L