Question
Q CH3COCH3 (g) eqm CH3CH3 +CO
initial pressure of CH3COCH is 300 mm when eqm is setup mole fraction of CO(g) = 1/6 hence total pressure will be =?
ANS 360mm of hg .SOL =?
At equilibrium mole fraction of CO = 1/6, that of CH3CH3 = 1/6
so mole fraction of CH3COCH3 = 1- 1/6 - 1/6 = 2/3
let the total pressure at equilibrium = p
so pressure of CH3CH3 and CO will be p/6 and p/6
and that of CH3COCH3 = 2p/3
now consider the following dissociation data
CH3COCH3 ----> CH3CH3 + CO
300 mm 0 0 at starting
300-x mm x x at equilibrium
here x = p/6 (1) and 300-x = 2p/3 (2) add these equations and get the value of p