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Question

A body is moving towards north with initial velocity of 13m/s. Its is subjected to a retardation of 2 m/s² towards south.The distance travelled in 7th sec is ??

Joshi sir comment

displacement of any particular sec. = u+at-(a/2)

here direction of motion is opposite to the direction of acceleration so formula will be u-at+(a/2)

displacement in 7th sec = 0

now we know that direction of motion will become south after 6.5 sec. so distance for last half sec = ut+(1/2)at²= 1/4

same will be the distance for the first half sec of 7th. so total distance for 7th sec = 1/4 + 1/4 = 1/2

Read 3 Solution.

using s_n = u+a/2(2n-1)

s_n is the distance travelled in n^th second u=initial vel a=accⁿ
we get s₇=0
hence the ans=0

IITMAX 13 year ago is this solution helpfull: 6 32

but the answer is not 0 m.

NIKHIL VARSHNEY 13 year ago is this solution helpfull: 5 18

SAHIL KUMAR 13 year ago is this solution helpfull: 1 18

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