Question
Find the number of solutions of the equation 2cos²(x/2)sin²(x) = x² + 1/x² , 0 < x ≤ π/2 .
Joshi sir comment
max of sin and cos are 1 so max of left is 2
but x² + 1/x² ≥ 2x(1/x) = 2
so only solution will be obtained for 2cos²(x/2)sin²(x) = 2
so (1+cosx)(1-cos²x) = 2 which is impossible,so i think no solution