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Question

Joshi sir comment

$I n f i r s t c a s e F = 2 T = 150 s o T = 75 n e w t o n, N o w i n s e c o n d c a s e s y s t e m i s f r e e t o m o v e a c c e l e r a t i o n o f t h e s y s t e m a = F / 20 f o r 10 k g r o d F - 2 T = 10 a = 10 (F / 20) = F / 2 \Rightarrow F - (F / 2) = 2 T \Rightarrow F = 4 T = 300 n e w t o n$

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