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Question

a small ball of mass 1kg and a charge 2/3 uC is placed at the center of a uniformly charged sphere of radius 1m and charge 1/3 mC. a narrow smooth horizontal groove is made in the sphere from centre to surface as shown in figure. the sphere is made to rotate about its vertical diameter at a constant rate of 1/2pi revolutions per second. find the spedd w.r.t ground with which the ball slide out from the groove. neglect any magnetic force acting on ball?

Joshi sir comment

$P o t e n t i a l d i f f e r e n c e f r o m c e n t r e t o s u r f a c e = 3 V / 2 - V = V / 2 h e r e V = k q / r (q i s c h a r g e o f s p h e r e) m {v_{r}}^{2} / 2 = V Q / 2 (Q i s c h a r g e o f p a r t i c l e) v_{r} i s r a d i a l v e l o c i t y B e s i d e s \tan g e n t i a l v e l o c i t y d u e t o r o t a t i o n o f s p h e r e = r ω = r 2 π n n o w s o l v e$

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