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Question

Consider an electron trapped in an infinite well whose width is 98.5 pm. If it is in a state with n = 15, what are (i) its energy? (ii) the uncertainty in its momentum? (iii) the uncertainty in its position?

Joshi sir comment

$L e t w i d t h = b F o r n t h s t a t e n \frac{λ}{2} = b \Rightarrow λ = \frac{2 b}{n} N o w E = \frac{p^{2}}{2 m} = \frac{{(\frac{h}{λ})}^{2}}{2 m} S o l v e a f t e r p u t t i n g t h e v a l u e o f λ U n c e r ta i n t y i n p o s i t i o n = b N o w u s e ∆ p . ∆ x = n h / 2 π for finding uncertainty in momentum$

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Sir ,this was the approach i made,i want to know it is right or wrong,please help !

ANKIT SONI 4 year ago is this solution helpfull: 2 0

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