The general solution of this kind of differential eq. is y = eax Let a function g(x) = eaxf(x) (1) differentiate eq. (1) thrice for getting g,,,(x) now for getting the same function as given find a. you get the same function for a = 1/2. clearly, for min 5 zeros of g(x), there are min 2 zeros for g,,,(x). solve and inform if face any problem.
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