Question

Sir pls solve
Joshi sir comment

Amount of DCl = 4 milimole

Amount of NaOD = 8 milimole

After reaction of acid and base 

Amount of NaOD remaining = 4 milimole

Total volume = 100 ml = 0.1 lit

so [OD] =4*10-3/0.1=4*10-2 (1) Given pD = 13.6 so log[D+] =-13.6= 14¯.4 [D+] =2.5*10-14 (2) Now solve

Submit Your Answer


please login to submit your answer

Login Here

Username / Email :

Password :

Register | Forget Password