Question
IN THE PREVIOUS QUESn THAT WAS BALL IS DROPPED FROM HEIGHT 5M ACC. DUE TO GRAVITY IS NOT KNOWN & WE HAVE TO FIND = IT LOSES ITS VEL. BY WHICH FACTOR WHEN IT RISES TO 1.8M
IN THE SOLn SUBMITTED BY SOMEONE HE HAS TAKEN ACC. WHILE FINDING VEL EQN= =V2-U2=2AS AS CONST. SO I WANT TO KNOW WHY IN THIS QUES ACC. IS TAKEN CONST. WHILE THERE IS NO MENTn IN QUES
Joshi sir comment
answer by Nikhil is correct
consider once agian
Read 1 Solution.
what else can u take . suppose u are throwing a ball from earth or from moon .it is an example of uniformly acclearated motion . where a is constant
waht r u thinking , u r thinking to take a=p at H= 5m a= p-1 AT H=4.9 m ( totaly wrong thinking)
NIKHIL VARSHNEY 12 year ago
is this solution helpfull: 1 1