Question
The velocity of a particle is defined by Vx=100-t^(3/2) and Vy=100+10t-2t^(2) Where V is in m/sec and t is in seconds. The radius of curvature at the top of its path is?
The velocity of a particle is defined by Vx=100-t^(3/2) and Vy=100+10t-2t^(2) Where V is in m/sec and t is in seconds. The radius of curvature at the top of its path is?