Question

The coefficient of λ^n μ^n in the expansion of [(1+λ)(1+μ)(λ+μ)]^n is ?

Joshi sir comment

 

(1+λ)n = C0 + C1x + ..................................Cnxn

similarly for (1+μ)n and 

(λ+μ)n = C0λn + C1λn-1μ + ........................ + Cnμn

On multiplying these 3, we will get the coefficient of  λnμ= ∑Cn3      (Here you should remember that C0 = Cn, C1 = Cn-1 and etc)

For getting the value of  ∑Cn:

multiply the expansions of (1+x)n, (1-x)n and [1-(1/x2)]n and calculate the coefficient of x0, we get ∑Cn3

and if we multiply (1+x)n, (1-x)n and [1-(1/x2)]n, then we get (-1)n(1-x2)2n/x2n so coefficient of xin this expression will be (-1)n 2nC(-1)2nCn

 

 

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