Question
y-xp=x+yp
Joshi sir comment
on applying p = dy/dx
(ydx-xdy)/dx = (xdx+ydy)/dx
or ydx-xdy = xdx+ydy
or dy/dx = (y-x)/(y+x)
now it is homogeneous
y-xp=x+yp
on applying p = dy/dx
(ydx-xdy)/dx = (xdx+ydy)/dx
or ydx-xdy = xdx+ydy
or dy/dx = (y-x)/(y+x)
now it is homogeneous