Question

Let g(x) be a continuous function such that    0ò1 g(t) dt = 2.   Let f(x) = 1/2 0òx (x-t)2 g(t) dt then find f '(x) and hence evaluate f "(x).

Joshi sir comment

 

f(x) = 1/2 0òx (x-t)2 g(t) dt

or f(x) = 1/2 0òx2 g(t) dt + 1/2 0òt2 g(t) dt - 0òx t g(t) dt 

or f(x) = 1/2 x2 0ò g(t) dt + 1/2 0òt2 g(t) dt - x 0ò t g(t) dt

now use newton leibniz formula for middle function and product rule for first and last functions for finding f' (x)

similarly get f'' (x)

 

 

 

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