Question
the time period of oscillatn of a simple pendulum is 2π (l/g)1/2. l is about 10cm & is known to 1mm accuracy. the time period of oscillatn is about 0.5s . time of 100 oscillatn with a wrist watch of 1s revolutn . what is the accuracy in determinatn of g?
ans 5%
Solution by Joshi sir.
T = 2π (l/g)1/2
so g α l/T2
so % error in g = % error in l + 2 % error in T
= 0.1*100/10 + 2* 1*100/50 = 1+4 = 5
here you shoult remember that if you count 100 osccilations then time will be counted for 100 osccilation.