Question
in a cubic closed packing of mixed oxide, it is found that lattice has O-2 ion & one half of the octahedral voids are occupied by trivalent cation A+3 & ONE EIGHTH of the FORMULA OF COMPOUND IS
1) AB2O4
2) A2B2O4
3) A2BO4
4)ABO4
Joshi sir comment
the question is incomplete, after ONE EIGHTH, i guess, it will be one eighth of the tetrahedral void are occupied by B
so let no. of O = 1
then no. of octahedral voids = 1 and half of this = 1/2
similarly tetrahedral voids = 2 so 1/8 of it = 2*1/8 = 1/4
so formula = A.5B.25O1 or A2B1O4
if my assumption for question is correct then answer would be 3) here B is divalent positive ion.