Question
IN A CUBIC CRYSTAL OF CsCl (d= 3.97gm/cc) THE 8 CORNER OCCUPIED BY Cl- WITH Cs+ AT CENTRE . CALCULATE THE RATIO OF RADIUS OF Cl- & Cs+
Joshi sir comment
use the formula d = Mn/N0a3
calculate a? here n = 1
now 2r - + 2r + = a √3
and 2r - = a
divide these equations for getting ratio