Question
QUES) AMMONIA UNDERGOES SELF DISSOCIATION ACCORDING TO D Rxn
2NH3 (l) ------> NH4+ (am) + NH2- (am)
WHERE am , STANDS FOR AMMONIATED . WHEN 1 MOL OF NH4Cl IS DISSOLVED IN 1 kg OF LIQUID AMMONIA , THE B.P. AT 760 TORR IS OBSV. AT -32.70 C ( NORMAL BOILING B.P OF NH3 (l) IS -33.40 C )
WHAT CONCLUSn ARE REACHED ABOUT THE NATURE OF SOLn??
( ANS NH4Cl IS COMPLETELY DISSOCIATED IN NH3)
Joshi sir comment
boiling point elevation = (-32.7) - (-33.4) = 0.7
now according to the given data
boiling point elevation = 1000*K(ammonia)*1/1 = 1000*0.00035 = 0.35
so i = 0.7/0.35 = 2
so 100 % dissociation