Question
In diamond,carbon atom occupy FCC lattice points as well as alternate tetrahedral voids.If edge length of the unit cell is 356pm,then radius of carbon atom is?
Joshi sir comment
for fcc lattice a√2 = 4r
Read 2 Solution.
a(edge length) = 356pm
in fcc radius = √3a / 4 now put value of a & on solving u vyl get d answer
Best SolutionSARIKA SHARMA 12 year ago
is this solution helpfull: 31 52
pardon use r= √2a / 4 . make correction it is not √3
SARIKA SHARMA 12 year ago
is this solution helpfull: 19 57