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IF 2sin²22⁰ = p+qcosθ, FIND SMALLEST POSITIVE VALUE OF θ, WHEN p=1 AND q = -1.

Joshi sir comment

2sin²22.5 = 1- cos45 = 1 + (-1)cos45

so θ = 45

Read 4 Solution.

2sin²22⁰=p+qCOSθ

OR, 1-COS2*22⁰=1-cosθ

or cosθ=cos44

or θ=44⁰

PRINCE PAL 12 year ago is this solution helpfull: 1 0

2sin²22⁰=p+qCOSθ

OR, 1-COS2*22⁰=1-cosθ

or cosθ=cos44

or θ=44⁰

PRINCE PAL 12 year ago is this solution helpfull: 0 0

sin²θ=( 1-cos2θ) / 2 so I think solution submitted by someone , need correction .

SARIKA SHARMA 12 year ago is this solution helpfull: 1 0

here in the ques sin²22= p+qcosθ is given, previously it is typed by mistake

SARIKA SHARMA 12 year ago is this solution helpfull: 1 0

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