Question

a ball is thrown vertically upwars with a velocity 20m/s from the top of a multistorey building. the height of the point from where the ball is thrown is 25m from the ground.

a) how high will the ball rise?

b) how long will it be before  the ball hits the ground? take g=10m/s square

 

Joshi sir comment

a) At heighest poing velocity will be 0

so by formula v2 = u2 - 2gh        (here - is because you are moving against gravity)

so h = 20*20/2*10 = 20 m

so ball will rise upto 25+20 m from the ground.

b) in second part we have to calculate the time of journey from top of 25 m high building to ground.

for this we should use  

-h = ut - gt2/2                   [in this case we are using upward direction as + ve and downward as - ve]

so -25 = 20t - 10t2/2

or 5t2 - 20t - 25 = 0

or t2- 4t - 5 = 0

or (t+1)(t-5) = 0  

or t = 5 , -1

so t = 5 sec.

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