Question
A smooth sphere of radius R is made to translate in a straight line with constnt acceralation a . A particle kept on the top of the sphere is released from there at zero velocity with respect to the sphere. find the speed of the particle with respect to the sphere as a function of the angle θ it slide
use energy conservation to solve it
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Read 2 Solution.
you cannot use energy conserv ation of energy because the body is accelerating
pls refer the diagram by manish
apply pseudo acceleration to the particle kept on top of the sphere the direction of the pseudo acceleration will be opposite in the direction of the acceleration and has the same magnitude as that of the sphere acceleration of the sphere hence the component of acceleration in the x-component is -a and the component of acceleration in the y-component is g(downward)
use equations of motion in x component you will get
v^2=u^2+2*a*s
u=0
the equation becomes
v^2=2*a*s eq1
s is nothiing but r(1-cosq)
substitute it in eq1 and get velocity as a function of theta along x-component
for velocity along y axis use conservation of energy principle
and then find out the resultant of the vectors of velocity along the x&y-components you will get tge ans
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http://www.opec.co.in/jeePhysics/WPE/s3