Question
The number of real negative terms in the binomial expansion of (1+ix)(4n-2), n € N and x > 0 is?
Joshi sir comment
Total number of terms in the expansion = 4n-2+1 = 4n-1
for a negative real number i2 is compulsory so associated terms are 3rd, 7th, 11th ..........
Total number of terms = n
Read 1 Solution.
Write the general expansion of Tr+1 =4n-2Cr(1)4n-2-r( ix)r here for negative terms i should be 2,6,10............(4n-2).
this is an ap with a=2, d=4 and l=4n-2 .you have to find number of terms using the formula l=a+(n-1)d
there fore number of terms =n ans.{rembember r cannot be 4,8,12,..... as i4 =1}
NIKHIL VARSHNEY 12 year ago
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