Question
Sir , i have solved limx-->0 (sin-1x - tan-1x )/x3 . plz have a look on others.
Joshi sir comment
limx-->0 (sin-1x - tan-1x )/x3
use D L Hospital rule or expansion of sin-1x and tan-1x to solve it
Sir , i have solved limx-->0 (sin-1x - tan-1x )/x3 . plz have a look on others.
limx-->0 (sin-1x - tan-1x )/x3
use D L Hospital rule or expansion of sin-1x and tan-1x to solve it